100x^2+70=210

Solution for 100x^2+70=210 equation:

100x^2+70=210

We move all terms to the left:

100x^2+70-(210)=0

We add all the numbers together, and all the variables

100x^2-140=0

a = 100; b = 0; c = -140;
Δ = b2-4ac
Δ = 02-4·100·(-140)
Δ = 56000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56000}=\sqrt{1600*35}=\sqrt{1600}*\sqrt{35}=40\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{35}}{2*100}=\frac{0-40\sqrt{35}}{200}
=-\frac{40\sqrt{35}}{200}
=-\frac{\sqrt{35}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{35}}{2*100}=\frac{0+40\sqrt{35}}{200}
=\frac{40\sqrt{35}}{200}
=\frac{\sqrt{35}}{5}
$